Tier 4 · first asked for by Diabolical
XYZ-Wing
A Y-Wing whose pivot also carries the eliminating digit.
The same shape as a Y-Wing, but the pivot has three candidates {X,Y,Z} and the two pincers hold {X,Z} and {Y,Z}. Now Z could be in any of the three cells.
The conclusion is therefore weaker: a cell only loses Z if it can see all three of them, not just the two pincers. That usually means the eliminations happen inside the box the three cells share.
A worked example
A real position, with the pencil marks a solver would have at that point.
the pattern · what it rules out · 5 a candidate that goes
What it proves. XYZ-Wing: pivot R6C7 (689) with pincers R1C7 and R6C8 puts 6 in one of the three, so 6 leaves R4C7, R5C7.
Builds on Y-Wing.